buf.writeInt32LE(value[, offset])
value
<integer> 要写入buf
的数字。offset
<integer> 开始写入之前要跳过的字节数。 必须满足0 <= offset <= buf.length - 4
。 默认值:0
。- 返回: <integer>
offset
加上写入的字节数。
将 value
作为小端序写入 buf
中指定的 offset
。
value
必须是有效的有符号 32 位整数。
当 value
不是有符号的 32 位整数时,则行为未定义。
value
被解释和写入为二进制补码有符号整数。
const buf = Buffer.allocUnsafe(4);
buf.writeInt32LE(0x05060708, 0);
console.log(buf);
// 打印: <Buffer 08 07 06 05>
value
<integer> Number to be written tobuf
.offset
<integer> Number of bytes to skip before starting to write. Must satisfy0 <= offset <= buf.length - 4
. Default:0
.- Returns: <integer>
offset
plus the number of bytes written.
Writes value
to buf
at the specified offset
as little-endian. The value
must be a valid signed 32-bit integer. Behavior is undefined when value
is
anything other than a signed 32-bit integer.
The value
is interpreted and written as a two's complement signed integer.
const buf = Buffer.allocUnsafe(4);
buf.writeInt32LE(0x05060708, 0);
console.log(buf);
// Prints: <Buffer 08 07 06 05>