Buffer.allocUnsafe() 与 Buffer.allocUnsafeSlow() 不安全的原因

当调用 Buffer.allocUnsafe()Buffer.allocUnsafeSlow() 时,分配的内存段未初始化(未清零)。 虽然这种设计使内存分配非常快,但分配的内存段可能包含潜在敏感的旧数据。 使用 Buffer.allocUnsafe() 创建的 Buffer 而不完全覆盖内存可以使此旧数据在读取 Buffer 内存时泄露。

虽然使用 Buffer.allocUnsafe() 有明显的性能优势,但必须格外小心,以避免将安全漏洞引入应用程序中。

When calling Buffer.allocUnsafe() and Buffer.allocUnsafeSlow(), the segment of allocated memory is uninitialized (it is not zeroed-out). While this design makes the allocation of memory quite fast, the allocated segment of memory might contain old data that is potentially sensitive. Using a Buffer created by Buffer.allocUnsafe() without completely overwriting the memory can allow this old data to be leaked when the Buffer memory is read.

While there are clear performance advantages to using Buffer.allocUnsafe(), extra care must be taken in order to avoid introducing security vulnerabilities into an application.