buf.writeInt16LE(value[, offset])
value<integer> 要写入buf的数字。offset<integer> 开始写入之前要跳过的字节数。 必须满足0 <= offset <= buf.length - 2。 默认值:0。- 返回: <integer>
offset加上写入的字节数。
将 value 作为小端序写入 buf 中指定的 offset。
value 必须是有效的有符号 16 位整数。
当 value 不是有符号的 16 位整数时,则行为未定义。
value 被解释和写入为二进制补码有符号整数。
const buf = Buffer.allocUnsafe(2);
buf.writeInt16LE(0x0304, 0);
console.log(buf);
// 打印: <Buffer 04 03>value<integer> Number to be written tobuf.offset<integer> Number of bytes to skip before starting to write. Must satisfy0 <= offset <= buf.length - 2. Default:0.- Returns: <integer>
offsetplus the number of bytes written.
Writes value to buf at the specified offset as little-endian. The value
must be a valid signed 16-bit integer. Behavior is undefined when value is
anything other than a signed 16-bit integer.
The value is interpreted and written as a two's complement signed integer.
const buf = Buffer.allocUnsafe(2);
buf.writeInt16LE(0x0304, 0);
console.log(buf);
// Prints: <Buffer 04 03>