返回类型 void
函数的 void 返回类型可能会产生一些不寻常但预期的行为。
The void return type for functions can produce some unusual, but expected behavior.
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type voidFunc = () => void;
const f1: voidFunc = () => {
return true;
};
const f2: voidFunc = () => true;
const f3: voidFunc = function () {
return true;
};
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type voidFunc = () => void;
const f1: voidFunc = () => {
return true;
};
const f2: voidFunc = () => true;
const f3: voidFunc = function () {
return true;
};
const v1 = f1();
const v2 = f2();
const v3 = f3();
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const src = [1, 2, 3];
const dst = [0];
src.forEach((el) => dst.push(el));
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function f2(): void {
return true;
}
const f3 = function (): void {
return true;
};
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- v1 手册
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- v2 手册
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- 常见问题 - "Why are functions returning non-void assignable to function returning void?"
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