no-useless-rename

不允许将导入、导出和解构的分配重命名为相同的名称

一些该规则报告的问题可以通过 --fix 命令行选项 自动修复

ES2015 允许重命名 import 和 export 语句中的引用以及解构赋值。这为程序员在重命名这些引用时执行这些操作提供了简洁的语法：

import { foo as bar } from "baz";
export { foo as bar };
let { foo: bar } = baz;

使用此语法，可以将引用重命名为相同名称。这是一个完全多余的操作，因为这与根本不重命名是一样的。例如，这个：

import { foo as foo } from "bar";
export { foo as foo };
let { foo: foo } = bar;

是相同的：

import { foo } from "bar";
export { foo };
let { foo } = bar;

规则详情

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选项

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"no-useless-rename": ["error", {
    "ignoreDestructuring": false,
    "ignoreImport": false,
    "ignoreExport": false
}]

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/*eslint no-useless-rename: "error"*/

import { foo as foo } from "bar";
import { "foo" as foo } from "bar";
export { foo as foo };
export { foo as "foo" };
export { foo as foo } from "bar";
export { "foo" as "foo" } from "bar";
let { foo: foo } = bar;
let { 'foo': foo } = bar;
function foo({ bar: bar }) {}
({ foo: foo }) => {}

XzI939IK+dLd3EupmpNvSYxAStxuhc/vaV27VKtNflliblmfNV1ebos8HldHJkh0oWAuBMI0vduIUojJFwMchA==

/*eslint no-useless-rename: "error"*/

import * as foo from "foo";
import { foo } from "bar";
import { foo as bar } from "baz";
import { "foo" as bar } from "baz";

export { foo };
export { foo as bar };
export { foo as "bar" };
export { foo as bar } from "foo";
export { "foo" as "bar" } from "foo";

let { foo } = bar;
let { foo: bar } = baz;
let { [foo]: foo } = bar;

function foo({ bar }) {}
function foo({ bar: baz }) {}

({ foo }) => {}
({ foo: bar }) => {}

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/*eslint no-useless-rename: ["error", { ignoreImport: true }]*/

import { foo as foo } from "bar";

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/*eslint no-useless-rename: ["error", { ignoreExport: true }]*/

export { foo as foo };
export { foo as foo } from "bar";

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/*eslint no-useless-rename: ["error", { ignoreDestructuring: true }]*/

let { foo: foo } = bar;
function foo({ bar: bar }) {}
({ foo: foo }) => {}

何时不使用

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兼容性

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