buf.writeUInt16LE(value[, offset])
value<integer> 要写入buf的数字。offset<integer> 写入前要跳过的字节数。必须满足0 <= offset <= buf.length - 2。默认值:0。- 返回:<integer>
offset加上写入的字节数。
将 value 以小端格式写入指定 offset 的 buf。value 必须是有效的无符号 16 位整数。当 value 不是无符号 16 位整数时,行为未定义。
【Writes value to buf at the specified offset as little-endian. The value
must be a valid unsigned 16-bit integer. Behavior is undefined when value is
anything other than an unsigned 16-bit integer.】
这个函数也可以通过 writeUint16LE 别名使用。
【This function is also available under the writeUint16LE alias.】
import { Buffer } from 'node:buffer';
const buf = Buffer.allocUnsafe(4);
buf.writeUInt16LE(0xdead, 0);
buf.writeUInt16LE(0xbeef, 2);
console.log(buf);
// Prints: <Buffer ad de ef be>const { Buffer } = require('node:buffer');
const buf = Buffer.allocUnsafe(4);
buf.writeUInt16LE(0xdead, 0);
buf.writeUInt16LE(0xbeef, 2);
console.log(buf);
// Prints: <Buffer ad de ef be>