path.join([...paths])

• ...paths <string> 路径片段的序列

  ¥...paths <string> A sequence of path segments

• 返回：<string>

  ¥Returns: <string>

path.join() 方法使用特定于平台的分隔符作为定界符将所有给定的 path 片段连接在一起，然后规范化生成的路径。

¥The path.join() method joins all given path segments together using the platform-specific separator as a delimiter, then normalizes the resulting path.

零长度的 path 片段被忽略。如果连接的路径字符串是零长度字符串，则将返回 '.'，表示当前工作目录。

¥Zero-length path segments are ignored. If the joined path string is a zero-length string then '.' will be returned, representing the current working directory.

path.join('/foo', 'bar', 'baz/asdf', 'quux', '..');
// Returns: '/foo/bar/baz/asdf'

path.join('foo', {}, 'bar');
// Throws 'TypeError: Path must be a string. Received {}' 拷贝

如果任何路径片段不是字符串，则抛出 TypeError。

¥A TypeError is thrown if any of the path segments is not a string.