path.join([...paths])


path.join() 方法会将所有给定的 path 片段连接到一起(使用平台特定的分隔符作为定界符),然后规范化生成的路径。

长度为零的 path 片段会被忽略。 如果连接后的路径字符串为长度为零的字符串,则返回 '.',表示当前工作目录。

path.join('/目录1', '目录2', '目录3/目录4', '目录5', '..');
// 返回: '/目录1/目录2/目录3/目录4'

path.join('目录1', {}, '目录2');
// 抛出 'TypeError: Path must be a string. Received {}'

如果任何的路径片段不是字符串,则抛出 TypeError

The path.join() method joins all given path segments together using the platform-specific separator as a delimiter, then normalizes the resulting path.

Zero-length path segments are ignored. If the joined path string is a zero-length string then '.' will be returned, representing the current working directory.

path.join('/foo', 'bar', 'baz/asdf', 'quux', '..');
// Returns: '/foo/bar/baz/asdf'

path.join('foo', {}, 'bar');
// Throws 'TypeError: Path must be a string. Received {}'

A TypeError is thrown if any of the path segments is not a string.