path.join([...paths])
path.join()
方法会将所有给定的 path
片段连接到一起(使用平台特定的分隔符作为定界符),然后规范化生成的路径。
长度为零的 path
片段会被忽略。
如果连接后的路径字符串为长度为零的字符串,则返回 '.'
,表示当前工作目录。
path.join('/目录1', '目录2', '目录3/目录4', '目录5', '..');
// 返回: '/目录1/目录2/目录3/目录4'
path.join('目录1', {}, '目录2');
// 抛出 'TypeError: Path must be a string. Received {}'
如果任何的路径片段不是字符串,则抛出 TypeError
。
The path.join()
method joins all given path
segments together using the
platform-specific separator as a delimiter, then normalizes the resulting path.
Zero-length path
segments are ignored. If the joined path string is a
zero-length string then '.'
will be returned, representing the current
working directory.
path.join('/foo', 'bar', 'baz/asdf', 'quux', '..');
// Returns: '/foo/bar/baz/asdf'
path.join('foo', {}, 'bar');
// Throws 'TypeError: Path must be a string. Received {}'
A TypeError
is thrown if any of the path segments is not a string.