path.join([...paths])


使用平台特定的分隔符把所有 path 片段连接到一起,并规范化生成的路径。

空字符串的 path 片段会被忽略。 如果连接后的路径是一个空字符串,则返回 '.',表示当前工作目录。

path.join('/foo', 'bar', 'baz/asdf', 'quux', '..');
// 返回: '/foo/bar/baz/asdf'

path.join('foo', {}, 'bar');
// 抛出 'TypeError: Path must be a string. Received {}'

如果 path 不是字符串,则抛出 TypeError

The path.join() method joins all given path segments together using the platform-specific separator as a delimiter, then normalizes the resulting path.

Zero-length path segments are ignored. If the joined path string is a zero-length string then '.' will be returned, representing the current working directory.

path.join('/foo', 'bar', 'baz/asdf', 'quux', '..');
// Returns: '/foo/bar/baz/asdf'

path.join('foo', {}, 'bar');
// throws 'TypeError: Path must be a string. Received {}'

A TypeError is thrown if any of the path segments is not a string.